x^2+2x+3x+10=180

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Solution for x^2+2x+3x+10=180 equation:



x^2+2x+3x+10=180
We move all terms to the left:
x^2+2x+3x+10-(180)=0
We add all the numbers together, and all the variables
x^2+5x-170=0
a = 1; b = 5; c = -170;
Δ = b2-4ac
Δ = 52-4·1·(-170)
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{705}}{2*1}=\frac{-5-\sqrt{705}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{705}}{2*1}=\frac{-5+\sqrt{705}}{2} $

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